What is the headwind component for a takeoff on Rwy 13 with a wind direction of 190° at 15 knots?

To determine the headwind component for takeoff on Runway 13 with a wind direction of 190° at 15 knots, you need to analyze the relationship between the runway direction and the wind direction. Runway 13 is oriented at 130° (since the runway number indicates the magnetic heading) while the wind is coming from 190°.

First, calculate the angle between the runway and the wind direction. The wind is from 190°, so if you subtract the runway's heading, you have:

190° - 130° = 60°.

Now, we can find the headwind component using the formula for wind components:

Headwind = Wind Speed × cos(Angle).

In this case, the angle is 60°. So the headwind component calculation would be:

Headwind = 15 knots × cos(60°) = 15 knots × 0.5 = 7.5 knots.

Since we typically round to the nearest whole number when assessing these components, it approximates to 7 knots. However, depending on the context, it’s not uncommon to round differently or account for various factors, leading sometimes to considerations around rounding in the quiz setting.

The closest choice available, based on the calculations