To move the center of gravity (CG) from 94.0 to 92.0, approximately how much baggage must be shifted if the ramp weight is 3,650 pounds?

To determine how much baggage needs to be shifted to adjust the center of gravity (CG) from 94.0 inches to 92.0 inches with a total ramp weight of 3,650 pounds, we can apply basic principles of weight and balance.

The change in CG required is 2.0 inches. The formula used for adjusting the CG is:

Change in CG = (Weight shift × Distance from original CG) / Total Weight

Where:

• Change in CG is how much you want to move the CG (in this case, 2.0 inches).

• Weight shift is the amount of baggage shifted (what we're solving for).

• Distance from original CG refers to how far the baggage is from the current CG position.

To shift the CG down by 2.0 inches, you will need to calculate the required weight shift. Rearranging the formula gives us:

Weight shift = (Change in CG × Total Weight) / Distance from original CG.

If we assume a reasonable distance (usually based on the aircraft's configurations and typical baggage placement), let’s say this distance is approximately 40 inches for our calculations. Plugging in the numbers would look like this:

Weight shift = (2.0 inches × 365